What is the domain of (7x+9)/(81x^4-16) ?

The domain of (7x+9)/(81x^4-16) is x 2/3

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domain of (7x+9)/(81x^4-16)

domain

x < - \frac{2}{3} or - \frac{2}{3} < x < \frac{2}{3} or x > \frac{2}{3}

Interval Notation

(- \infty, - \frac{2}{3}) \cup (- \frac{2}{3}, \frac{2}{3}) \cup (\frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{3}, x = - \frac{2}{3}

The function domain

x < - \frac{2}{3} or - \frac{2}{3} < x < \frac{2}{3} or x > \frac{2}{3}

What is the domain of (7x+9)/(81x^4-16) ?
The domain of (7x+9)/(81x^4-16) is x<-2/3 \lor-2/3 <x< 2/3 \lor x> 2/3