What is the domain of y/(3y^2+17y+10) ?

The domain of y/(3y^2+17y+10) is y -2/3

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domain of y/(3y^2+17y+10)

domain

y < - 5 or - 5 < y < - \frac{2}{3} or y > - \frac{2}{3}

Interval Notation

(- \infty, - 5) \cup (- 5, - \frac{2}{3}) \cup (- \frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

y = - \frac{2}{3}, y = - 5

The function domain

y < - 5 or - 5 < y < - \frac{2}{3} or y > - \frac{2}{3}

What is the domain of y/(3y^2+17y+10) ?
The domain of y/(3y^2+17y+10) is y<-5\lor-5<y<-2/3 \lor y>-2/3