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midpoint
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domain of f(x)=(1/(sqrt(x)))^2-9parity f(x)=sin(2x)midpoint (-8,-3),(10,9)extreme f(x)=x^2-12x+1parity sqrt(1+x^2sin^2(x)+x^2cos^2(x))
Frequently Asked Questions (FAQ)
What is the midpoint (-5,5),(-2,10) ?
The midpoint (-5,5),(-2,10) is (-7/2 , 15/2)