What is the domain of f(x)= 1/((x-2)(x+1)(x+2)) ?

The domain of f(x)= 1/((x-2)(x+1)(x+2)) is x 2

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domain of f(x)= 1/((x-2)(x+1)(x+2))

domain

x < - 2 or - 2 < x < - 1 or - 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 1, x = - 2

The function domain

x < - 2 or - 2 < x < - 1 or - 1 < x < 2 or x > 2

What is the domain of f(x)= 1/((x-2)(x+1)(x+2)) ?
The domain of f(x)= 1/((x-2)(x+1)(x+2)) is x<-2\lor-2<x<-1\lor-1<x<2\lor x>2