What is the domain of f(x)= 1/(sqrt(x^2+4x+3)) ?

The domain of f(x)= 1/(sqrt(x^2+4x+3)) is x -1

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domain of f(x)= 1/(sqrt(x^2+4x+3))

domain

x < - 3 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq - 1

Find undefined (singularity) points:

x = - 1, x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x > - 1

What is the domain of f(x)= 1/(sqrt(x^2+4x+3)) ?
The domain of f(x)= 1/(sqrt(x^2+4x+3)) is x<-3\lor x>-1