What is the inverse of f(x)=x^2+3x-4 ?

The inverse of f(x)=x^2+3x-4 is (-3+sqrt(4x+25))/2 ,(-3-sqrt(4x+25))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=x^2+3x-4

inverse

f (x) = x^{2} + 3 x - 4

\frac{- 3 + 4 x + 25}{2}, \frac{- 3 - 4 x + 25}{2}

Solution steps

y = x^{2} + 3 x - 4

Replace

x

with

y

x = y^{2} + 3 y - 4

Solve for

y, x = y^{2} + 3 y - 4

\frac{- 3 + 4 x + 25}{2}, \frac{- 3 - 4 x + 25}{2}

What is the inverse of f(x)=x^2+3x-4 ?
The inverse of f(x)=x^2+3x-4 is (-3+sqrt(4x+25))/2 ,(-3-sqrt(4x+25))/2