What is the domain of f(x)=sqrt(3x^2+7x+2) ?

The domain of f(x)=sqrt(3x^2+7x+2) is x =-1/3

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domain of f(x)=sqrt(3x^2+7x+2)

domain

x \leq - 2 or x \geq - \frac{1}{3}

Interval Notation

(- \infty, - 2] \cup [- \frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq - \frac{1}{3}

The function domain

x \leq - 2 or x \geq - \frac{1}{3}

What is the domain of f(x)=sqrt(3x^2+7x+2) ?
The domain of f(x)=sqrt(3x^2+7x+2) is x<=-2\lor x>=-1/3