What is the domain of f(x)=(2x^2)/(sqrt(x^2-6x-7)) ?

The domain of f(x)=(2x^2)/(sqrt(x^2-6x-7)) is x 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

domain of f(x)=(2x^2)/(sqrt(x^2-6x-7))

domain

x < - 1 or x > 7

Interval Notation

(- \infty, - 1) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 7

Find undefined (singularity) points:

x = 7, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 7

What is the domain of f(x)=(2x^2)/(sqrt(x^2-6x-7)) ?
The domain of f(x)=(2x^2)/(sqrt(x^2-6x-7)) is x<-1\lor x>7