What is the domain of (3sqrt(x^2-9))/(x-1) ?

The domain of (3sqrt(x^2-9))/(x-1) is x = 3

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domain of (3sqrt(x^2-9))/(x-1)

domain

\frac{3 x ^{2} - 9}{x - 1}

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq - 3 or x \geq 3

What is the domain of (3sqrt(x^2-9))/(x-1) ?
The domain of (3sqrt(x^2-9))/(x-1) is x<=-3\lor x>= 3