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Popular Functions >

domain of f(x)=sqrt(2+ln(x))

Solution

domain

f (x) = 2 + ln (x)

Solution

x \geq \frac{1}{e ^{2}}

+1

Interval Notation

[\frac{1}{e ^{2}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{2}}

The function domain

x \geq \frac{1}{e ^{2}}

Graph

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Frequently Asked Questions (FAQ)

What is the domain of f(x)=sqrt(2+ln(x)) ?
The domain of f(x)=sqrt(2+ln(x)) is x>= 1/(e^2)