What is the domain of f(x)=-sqrt(4-x^2),0<= x<2 ?

The domain of f(x)=-sqrt(4-x^2),0<= x<2 is 0<= x<2

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domain of f(x)=-sqrt(4-x^2),0<= x<2

domain

f (x) = - 4 - x^{2}, 0 \leq x < 2

0 \leq x < 2

Interval Notation

[0, 2)

Solution steps

Set the domain to the given interval

0 \leq x < 2

Find non-negative values for radicals:

- 2 \leq x \leq 2

Join real regions with the domain:

- 2 \leq x \leq 2 and 0 \leq x < 2

0 \leq x < 2

What is the domain of f(x)=-sqrt(4-x^2),0<= x<2 ?
The domain of f(x)=-sqrt(4-x^2),0<= x<2 is 0<= x<2