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midpoint
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range of sqrt(x^2+8x)range of f(x)=ln(x)+7perpendicular 5x-2y=4,(2,-4)domain of 1/(2(4x+1))symmetry-6x^2
Frequently Asked Questions (FAQ)
What is the midpoint (-2,7),(-2,-2) ?
The midpoint (-2,7),(-2,-2) is (-2, 5/2)