What is the extreme f(x)=x^3-12x+2 ?

The extreme f(x)=x^3-12x+2 is Maximum(-2,18),Minimum(2,-14)

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extreme f(x)=x^3-12x+2

extreme points

f (x) = x^{3} - 12 x + 2

Maximum (- 2, 18), Minimum (2, - 14)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x + 2 : 18

Maximum (- 2, 18)

Plug

x = 2

into

x^{3} - 12 x + 2 : - 14

Minimum (2, - 14)

Maximum (- 2, 18), Minimum (2, - 14)

f (x) = \frac{1}{x ^{2} + 3}

y = \frac{1}{3} x - 2

g (x) = \frac{x - 2}{x - 7}

f (x) = 2 sin (\frac{π}{2} x)

\frac{x}{1 - x}

What is the extreme f(x)=x^3-12x+2 ?
The extreme f(x)=x^3-12x+2 is Maximum(-2,18),Minimum(2,-14)