What is the domain of f(x)=log_{1/5}(x^2-x-12)+6 ?

The domain of f(x)=log_{1/5}(x^2-x-12)+6 is x 4

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domain of f(x)=log_{1/5}(x^2-x-12)+6

domain

f (x) = lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6

x < - 3 or x > 4

Interval Notation

(- \infty, - 3) \cup (4, \infty)

Solution steps

Find positive values for logs:

x < - 3 or x > 4

The function domain

x < - 3 or x > 4

What is the domain of f(x)=log_{1/5}(x^2-x-12)+6 ?
The domain of f(x)=log_{1/5}(x^2-x-12)+6 is x<-3\lor x>4