What is the inverse of 800x-2x^2 ?

The inverse of 800x-2x^2 is -(-800+sqrt(640000-8x))/4 ,-(-800-sqrt(640000-8x))/4

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inverse of 800x-2x^2

inverse

800 x - 2 x^{2}

- \frac{- 800 + 640000 - 8 x}{4}, - \frac{- 800 - 640000 - 8 x}{4}

Solution steps

y = 800 x - 2 x^{2}

Replace

x

with

y

x = 800 y - 2 y^{2}

Solve for

y, x = 800 y - 2 y^{2}

- \frac{- 800 + 640000 - 8 x}{4}, - \frac{- 800 - 640000 - 8 x}{4}

What is the inverse of 800x-2x^2 ?
The inverse of 800x-2x^2 is -(-800+sqrt(640000-8x))/4 ,-(-800-sqrt(640000-8x))/4