What is the inverse of (x^2-x-12)/(x^2-9) ?

The inverse of (x^2-x-12)/(x^2-9) is (-4+3x)/(x-1)

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inverse of (x^2-x-12)/(x^2-9)

inverse

\frac{x ^{2} - x - 12}{x ^{2} - 9}

\frac{- 4 + 3 x}{x - 1}

Solution steps

y = \frac{x ^{2} - x - 12}{x ^{2} - 9}

Replace

x

with

y

x = \frac{y ^{2} - y - 12}{y ^{2} - 9}

Solve for

y, x = \frac{y ^{2} - y - 12}{y ^{2} - 9}

\frac{- 4 + 3 x}{x - 1}

What is the inverse of (x^2-x-12)/(x^2-9) ?
The inverse of (x^2-x-12)/(x^2-9) is (-4+3x)/(x-1)