What is the inverse of f(x)=log_{10}(3)(x-1)+2 ?

The inverse of f(x)=log_{10}(3)(x-1)+2 is (x-2)/(log_{10)(3)}+1

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inverse of f(x)=log_{10}(3)(x-1)+2

inverse

f (x) = lo g_{10} (3) (x - 1) + 2

\frac{x - 2}{lo g _{10} ( 3 )} + 1

Solution steps

y = lo g_{10} (3) (x - 1) + 2

Replace

x

with

y

x = lo g_{10} (3) (y - 1) + 2

Solve for

y, x = lo g_{10} (3) (y - 1) + 2

\frac{x - 2}{lo g _{10} ( 3 )} + 1

What is the inverse of f(x)=log_{10}(3)(x-1)+2 ?
The inverse of f(x)=log_{10}(3)(x-1)+2 is (x-2)/(log_{10)(3)}+1