What is the inverse of (2z^{-1})/(1-(1/3)(z^{-1))} ?

The inverse of (2z^{-1})/(1-(1/3)(z^{-1))} is (6+z)/(3z)

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inverse of (2z^{-1})/(1-(1/3)(z^{-1))}

inverse

\frac{2 z ^{- 1}}{1 - ( \frac{1}{3} ) ( z ^{- 1} )}

\frac{6 + z}{3 z}

Solution steps

y = \frac{2 z ^{- 1}}{1 - \frac{1}{3} z ^{- 1}}

Replace

z

with

y

z = \frac{2 y ^{- 1}}{1 - \frac{1}{3} y ^{- 1}}

Solve for

y, z = \frac{2 y ^{- 1}}{1 - \frac{1}{3} y ^{- 1}}

\frac{6 + z}{3 z}

What is the inverse of (2z^{-1})/(1-(1/3)(z^{-1))} ?
The inverse of (2z^{-1})/(1-(1/3)(z^{-1))} is (6+z)/(3z)