What is the inverse of g(x)=2(x-4)^2+1 ?

The inverse of g(x)=2(x-4)^2+1 is sqrt((x-1)/2)+4,-sqrt((x-1)/2)+4

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inverse of g(x)=2(x-4)^2+1

inverse

g (x) = 2 (x - 4)^{2} + 1

\frac{x - 1}{2} + 4, - \frac{x - 1}{2} + 4

Solution steps

y = 2 (x - 4)^{2} + 1

Replace

x

with

y

x = 2 (y - 4)^{2} + 1

Solve for

y, x = 2 (y - 4)^{2} + 1

\frac{x - 1}{2} + 4, - \frac{x - 1}{2} + 4

What is the inverse of g(x)=2(x-4)^2+1 ?
The inverse of g(x)=2(x-4)^2+1 is sqrt((x-1)/2)+4,-sqrt((x-1)/2)+4