What is the inverse of (x^2-8)/(x-3) ?

The inverse of (x^2-8)/(x-3) is (x+sqrt(x^2-4(-8+3x)))/2 ,(x-sqrt(x^2-4(-8+3x)))/2

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inverse of (x^2-8)/(x-3)

inverse

\frac{x ^{2} - 8}{x - 3}

\frac{x + x ^{2} - 4 ( - 8 + 3 x )}{2}, \frac{x - x ^{2} - 4 ( - 8 + 3 x )}{2}

Solution steps

y = \frac{x ^{2} - 8}{x - 3}

Replace

x

with

y

x = \frac{y ^{2} - 8}{y - 3}

Solve for

y, x = \frac{y ^{2} - 8}{y - 3}

\frac{x + x ^{2} - 4 ( - 8 + 3 x )}{2}, \frac{x - x ^{2} - 4 ( - 8 + 3 x )}{2}

What is the inverse of (x^2-8)/(x-3) ?
The inverse of (x^2-8)/(x-3) is (x+sqrt(x^2-4(-8+3x)))/2 ,(x-sqrt(x^2-4(-8+3x)))/2