What is the inverse of f(x)= 2/((x+3)^2)-1 ?

The inverse of f(x)= 2/((x+3)^2)-1 is sqrt(2/(x+1))-3,-sqrt(2/(x+1))-3

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inverse of f(x)= 2/((x+3)^2)-1

inverse

f (x) = \frac{2}{( x + 3 ) ^{2}} - 1

\frac{2}{x + 1} - 3, - \frac{2}{x + 1} - 3

Solution steps

y = \frac{2}{( x + 3 ) ^{2}} - 1

Replace

x

with

y

x = \frac{2}{( y + 3 ) ^{2}} - 1

Solve for

y, x = \frac{2}{( y + 3 ) ^{2}} - 1

\frac{2}{x + 1} - 3, - \frac{2}{x + 1} - 3

What is the inverse of f(x)= 2/((x+3)^2)-1 ?
The inverse of f(x)= 2/((x+3)^2)-1 is sqrt(2/(x+1))-3,-sqrt(2/(x+1))-3