What is the inverse of y=-log_{2}(3(x-2))+4 ?

The inverse of y=-log_{2}(3(x-2))+4 is (2^{4-x})/3+2

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inverse of y=-log_{2}(3(x-2))+4

inverse

y = - lo g_{2} (3 (x - 2)) + 4

\frac{2 ^{4 - x}}{3} + 2

Solution steps

y = - lo g_{2} (3 (x - 2)) + 4

Replace

x

with

y

x = - lo g_{2} (3 (y - 2)) + 4

Solve for

y, x = - lo g_{2} (3 (y - 2)) + 4

\frac{2 ^{4 - x}}{3} + 2

What is the inverse of y=-log_{2}(3(x-2))+4 ?
The inverse of y=-log_{2}(3(x-2))+4 is (2^{4-x})/3+2