What is the inverse of f(x)=0.2log_{7}(3x+2)-9 ?

The inverse of f(x)=0.2log_{7}(3x+2)-9 is (16807^{x+9}-2)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=0.2log_{7}(3x+2)-9

inverse

f (x) = 0.2 lo g_{7} (3 x + 2) - 9

\frac{1680 7 ^{x + 9} - 2}{3}

Solution steps

y = 0.2 lo g_{7} (3 x + 2) - 9

Replace

x

with

y

x = 0.2 lo g_{7} (3 y + 2) - 9

Solve for

y, x = 0.2 lo g_{7} (3 y + 2) - 9

\frac{1680 7 ^{x + 9} - 2}{3}

What is the inverse of f(x)=0.2log_{7}(3x+2)-9 ?
The inverse of f(x)=0.2log_{7}(3x+2)-9 is (16807^{x+9}-2)/3