What is the inverse of (3x-2)^2+2x ?

The inverse of (3x-2)^2+2x is (5+sqrt(9x-11))/9 ,(5-sqrt(9x-11))/9

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inverse of (3x-2)^2+2x

inverse

(3 x - 2)^{2} + 2 x

\frac{5 + 9 x - 11}{9}, \frac{5 - 9 x - 11}{9}

Solution steps

y = (3 x - 2)^{2} + 2 x

Replace

x

with

y

x = (3 y - 2)^{2} + 2 y

Solve for

y, x = (3 y - 2)^{2} + 2 y

\frac{5 + 9 x - 11}{9}, \frac{5 - 9 x - 11}{9}

What is the inverse of (3x-2)^2+2x ?
The inverse of (3x-2)^2+2x is (5+sqrt(9x-11))/9 ,(5-sqrt(9x-11))/9