What is the inverse of log_{10}(6^{x-1}) ?

The inverse of log_{10}(6^{x-1}) is (xln(10))/(ln(6))+1

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inverse of log_{10}(6^{x-1})

inverse

lo g_{10} (6^{x - 1})

\frac{x ln ( 10 )}{ln ( 6 )} + 1

Solution steps

y = lo g_{10} (6^{x - 1})

Replace

x

with

y

x = lo g_{10} (6^{y - 1})

Solve for

y, x = lo g_{10} (6^{y - 1})

\frac{x ln ( 10 )}{ln ( 6 )} + 1

What is the inverse of log_{10}(6^{x-1}) ?
The inverse of log_{10}(6^{x-1}) is (xln(10))/(ln(6))+1