What is the inverse of (x^2)/(x+7) ?

The inverse of (x^2)/(x+7) is (x+sqrt(x^2+28x))/2 ,(x-sqrt(x^2+28x))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of (x^2)/(x+7)

inverse

\frac{x ^{2}}{x + 7}

\frac{x + x ^{2} + 28 x}{2}, \frac{x - x ^{2} + 28 x}{2}

Solution steps

y = \frac{x ^{2}}{x + 7}

Replace

x

with

y

x = \frac{y ^{2}}{y + 7}

Solve for

y, x = \frac{y ^{2}}{y + 7}

\frac{x + x ^{2} + 28 x}{2}, \frac{x - x ^{2} + 28 x}{2}

What is the inverse of (x^2)/(x+7) ?
The inverse of (x^2)/(x+7) is (x+sqrt(x^2+28x))/2 ,(x-sqrt(x^2+28x))/2