What is the inverse of f(x)=1-2*x^2 ?

The inverse of f(x)=1-2*x^2 is sqrt(-(x-1)/2),-sqrt(-(x-1)/2)

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inverse of f(x)=1-2*x^2

inverse

f (x) = 1 - 2 \cdot x^{2}

- \frac{x - 1}{2}, - - \frac{x - 1}{2}

Solution steps

y = 1 - 2 x^{2}

Replace

x

with

y

x = 1 - 2 y^{2}

Solve for

y, x = 1 - 2 \cdot y^{2}

- \frac{x - 1}{2}, - - \frac{x - 1}{2}

What is the inverse of f(x)=1-2*x^2 ?
The inverse of f(x)=1-2*x^2 is sqrt(-(x-1)/2),-sqrt(-(x-1)/2)