What is the inverse of (20)/(1+e^{-0.3*(t-15))} ?

The inverse of (20)/(1+e^{-0.3*(t-15))} is -(ln((20)/t-1))/(0.3)+15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of (20)/(1+e^{-0.3*(t-15))}

inverse

\frac{20}{1 + e ^{- 0.3 \cdot (t - 15)}}

- \frac{ln ( \frac{20}{t} - 1 )}{0.3} + 15

Solution steps

y = \frac{20}{1 + e ^{- 0.3 (t - 15)}}

Replace

t

with

y

t = \frac{20}{1 + e ^{- 0.3 (y - 15)}}

Solve for

y, t = \frac{20}{1 + e ^{- 0.3 \cdot (y - 15)}}

- \frac{ln ( \frac{20}{t} - 1 )}{0.3} + 15

What is the inverse of (20)/(1+e^{-0.3*(t-15))} ?
The inverse of (20)/(1+e^{-0.3*(t-15))} is -(ln((20)/t-1))/(0.3)+15