What is the inverse of f(x)=(-5x+7)^2+4,x>= 7/5 ?

The inverse of f(x)=(-5x+7)^2+4,x>= 7/5 is -(sqrt(x-4)-7)/5 ,-(-sqrt(x-4)-7)/5

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inverse of f(x)=(-5x+7)^2+4,x>= 7/5

inverse

f (x) = (- 5 x + 7)^{2} + 4, x \geq \frac{7}{5}

- \frac{x - 4 - 7}{5}, - \frac{- x - 4 - 7}{5}

Solution steps

y = (- 5 x + 7)^{2} + 4

Replace

x

with

y

x = (- 5 y + 7)^{2} + 4

Solve for

y, x = (- 5 y + 7)^{2} + 4

- \frac{x - 4 - 7}{5}, - \frac{- x - 4 - 7}{5}

What is the inverse of f(x)=(-5x+7)^2+4,x>= 7/5 ?
The inverse of f(x)=(-5x+7)^2+4,x>= 7/5 is -(sqrt(x-4)-7)/5 ,-(-sqrt(x-4)-7)/5