What is the inverse of f(x)=-(y^2)/(16)-y/2-1 ?

The inverse of f(x)=-(y^2)/(16)-y/2-1 is -4(sqrt(-y)+1),-4(-sqrt(-y)+1)

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inverse of f(x)=-(y^2)/(16)-y/2-1

inverse

f (x) = - \frac{y ^{2}}{16} - \frac{y}{2} - 1

- 4 (- y + 1), - 4 (- - y + 1)

Solution steps

x = - \frac{y ^{2}}{16} - \frac{y}{2} - 1

Replace

y

with

x

y = - \frac{x ^{2}}{16} - \frac{x}{2} - 1

Solve for

x, y = - \frac{x ^{2}}{16} - \frac{x}{2} - 1

- 4 (- y + 1), - 4 (- - y + 1)

What is the inverse of f(x)=-(y^2)/(16)-y/2-1 ?
The inverse of f(x)=-(y^2)/(16)-y/2-1 is -4(sqrt(-y)+1),-4(-sqrt(-y)+1)