What is the inverse of y=3(36+x^2)^{-1/2} ?

The inverse of y=3(36+x^2)^{-1/2} is (3(1-4x^2)^{1/2})/x ,-(3(1-4x^2)^{1/2})/x

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inverse of y=3(36+x^2)^{-1/2}

inverse

y = 3 (36 + x^{2})^{- \frac{1}{2}}

\frac{3 ( 1 - 4 x ^{2} ) ^{\frac{1}{2}}}{x}, - \frac{3 ( 1 - 4 x ^{2} ) ^{\frac{1}{2}}}{x}

Solution steps

y = 3 (36 + x^{2})^{- \frac{1}{2}}

Replace

x

with

y

x = 3 (36 + y^{2})^{- \frac{1}{2}}

Solve for

y, x = 3 (36 + y^{2})^{- \frac{1}{2}}

\frac{3 ( 1 - 4 x ^{2} ) ^{\frac{1}{2}}}{x}, - \frac{3 ( 1 - 4 x ^{2} ) ^{\frac{1}{2}}}{x}

What is the inverse of y=3(36+x^2)^{-1/2} ?
The inverse of y=3(36+x^2)^{-1/2} is (3(1-4x^2)^{1/2})/x ,-(3(1-4x^2)^{1/2})/x