What is the inverse of f(x)= 2/((x-1)^2)+3 ?

The inverse of f(x)= 2/((x-1)^2)+3 is sqrt(2/(x-3))+1,-sqrt(2/(x-3))+1

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inverse of f(x)= 2/((x-1)^2)+3

inverse

f (x) = \frac{2}{( x - 1 ) ^{2}} + 3

\frac{2}{x - 3} + 1, - \frac{2}{x - 3} + 1

Solution steps

y = \frac{2}{( x - 1 ) ^{2}} + 3

Replace

x

with

y

x = \frac{2}{( y - 1 ) ^{2}} + 3

Solve for

y, x = \frac{2}{( y - 1 ) ^{2}} + 3

\frac{2}{x - 3} + 1, - \frac{2}{x - 3} + 1

What is the inverse of f(x)= 2/((x-1)^2)+3 ?
The inverse of f(x)= 2/((x-1)^2)+3 is sqrt(2/(x-3))+1,-sqrt(2/(x-3))+1