What is the inverse of f(x)=3(x+1)^2-4 ?

The inverse of f(x)=3(x+1)^2-4 is sqrt((x+4)/3)-1,-sqrt((x+4)/3)-1

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inverse of f(x)=3(x+1)^2-4

inverse

f (x) = 3 (x + 1)^{2} - 4

\frac{x + 4}{3} - 1, - \frac{x + 4}{3} - 1

Solution steps

y = 3 (x + 1)^{2} - 4

Replace

x

with

y

x = 3 (y + 1)^{2} - 4

Solve for

y, x = 3 (y + 1)^{2} - 4

\frac{x + 4}{3} - 1, - \frac{x + 4}{3} - 1

What is the inverse of f(x)=3(x+1)^2-4 ?
The inverse of f(x)=3(x+1)^2-4 is sqrt((x+4)/3)-1,-sqrt((x+4)/3)-1