What is the inverse of (x^2)/(x-5)*(5x-10)/(2x) ?

The inverse of (x^2)/(x-5)*(5x-10)/(2x) is (5+x+sqrt(x^2-40x+25))/5 ,(5+x-sqrt(x^2-40x+25))/5

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inverse of (x^2)/(x-5)*(5x-10)/(2x)

inverse

\frac{x ^{2}}{x - 5} \cdot \frac{5 x - 10}{2 x}

\frac{5 + x + x ^{2} - 40 x + 25}{5}, \frac{5 + x - x ^{2} - 40 x + 25}{5}

Solution steps

y = \frac{x ^{2}}{x - 5} \cdot \frac{5 x - 10}{2 x}

Replace

x

with

y

x = \frac{y ^{2}}{y - 5} \cdot \frac{5 y - 10}{2 y}

Solve for

y, x = \frac{y ^{2}}{y - 5} \cdot \frac{5 y - 10}{2 y}

\frac{5 + x + x ^{2} - 40 x + 25}{5}, \frac{5 + x - x ^{2} - 40 x + 25}{5}

What is the inverse of (x^2)/(x-5)*(5x-10)/(2x) ?
The inverse of (x^2)/(x-5)*(5x-10)/(2x) is (5+x+sqrt(x^2-40x+25))/5 ,(5+x-sqrt(x^2-40x+25))/5