What is the inverse of f(x)=(y^2)/(72)+(4y)/(36)-2/3 ?

The inverse of f(x)=(y^2)/(72)+(4y)/(36)-2/3 is (-8+sqrt(288y+256))/2 ,(-8-sqrt(288y+256))/2

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inverse of f(x)=(y^2)/(72)+(4y)/(36)-2/3

inverse

f (x) = \frac{y ^{2}}{72} + \frac{4 y}{36} - \frac{2}{3}

\frac{- 8 + 288 y + 256}{2}, \frac{- 8 - 288 y + 256}{2}

Solution steps

x = \frac{y ^{2}}{72} + \frac{4 y}{36} - \frac{2}{3}

Replace

y

with

x

y = \frac{x ^{2}}{72} + \frac{4 x}{36} - \frac{2}{3}

Solve for

x, y = \frac{x ^{2}}{72} + \frac{4 x}{36} - \frac{2}{3}

\frac{- 8 + 288 y + 256}{2}, \frac{- 8 - 288 y + 256}{2}

What is the inverse of f(x)=(y^2)/(72)+(4y)/(36)-2/3 ?
The inverse of f(x)=(y^2)/(72)+(4y)/(36)-2/3 is (-8+sqrt(288y+256))/2 ,(-8-sqrt(288y+256))/2