What is the inverse of 4-9x-3x^2 ?

The inverse of 4-9x-3x^2 is -(9+sqrt(-12x+129))/6 ,-(9-sqrt(-12x+129))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of 4-9x-3x^2

inverse

4 - 9 x - 3 x^{2}

- \frac{9 + - 12 x + 129}{6}, - \frac{9 - - 12 x + 129}{6}

Solution steps

y = 4 - 9 x - 3 x^{2}

Replace

x

with

y

x = 4 - 9 y - 3 y^{2}

Solve for

y, x = 4 - 9 y - 3 y^{2}

- \frac{9 + - 12 x + 129}{6}, - \frac{9 - - 12 x + 129}{6}

What is the inverse of 4-9x-3x^2 ?
The inverse of 4-9x-3x^2 is -(9+sqrt(-12x+129))/6 ,-(9-sqrt(-12x+129))/6