What is the inverse of f(x)=x^2-3x+7,x=11 ?

The inverse of f(x)=x^2-3x+7,x=11 is (3+sqrt(4x-19))/2 ,(3-sqrt(4x-19))/2

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inverse of f(x)=x^2-3x+7,x=11

inverse

f (x) = x^{2} - 3 x + 7, x = 11

\frac{3 + 4 x - 19}{2}, \frac{3 - 4 x - 19}{2}

Solution steps

y = x^{2} - 3 x + 7

Replace

x

with

y

x = y^{2} - 3 y + 7

Solve for

y, x = y^{2} - 3 y + 7

\frac{3 + 4 x - 19}{2}, \frac{3 - 4 x - 19}{2}

What is the inverse of f(x)=x^2-3x+7,x=11 ?
The inverse of f(x)=x^2-3x+7,x=11 is (3+sqrt(4x-19))/2 ,(3-sqrt(4x-19))/2