What is the inverse of f(x)=2x^2+8x+1 ?

The inverse of f(x)=2x^2+8x+1 is (-8+sqrt(8x+56))/4 ,(-8-sqrt(8x+56))/4

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inverse of f(x)=2x^2+8x+1

inverse

f (x) = 2 x^{2} + 8 x + 1

\frac{- 8 + 8 x + 56}{4}, \frac{- 8 - 8 x + 56}{4}

Solution steps

y = 2 x^{2} + 8 x + 1

Replace

x

with

y

x = 2 y^{2} + 8 y + 1

Solve for

y, x = 2 y^{2} + 8 y + 1

\frac{- 8 + 8 x + 56}{4}, \frac{- 8 - 8 x + 56}{4}

What is the inverse of f(x)=2x^2+8x+1 ?
The inverse of f(x)=2x^2+8x+1 is (-8+sqrt(8x+56))/4 ,(-8-sqrt(8x+56))/4