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Popular Functions >

inverse of f(x)=(x+1)/x g(x)= 1/(x-1)

Solution

inverse

f (x) = \frac{x + 1}{x} g (x) = \frac{1}{x - 1}

Solution

\frac{1}{x} + 1

Solution steps

y = \frac{1}{x - 1}

Replace

x

with

y

x = \frac{1}{y - 1}

Solve for

y, x = \frac{1}{y - 1}

\frac{1}{x} + 1

Graph

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Frequently Asked Questions (FAQ)

What is the inverse of f(x)=(x+1)/x g(x)= 1/(x-1) ?
The inverse of f(x)=(x+1)/x g(x)= 1/(x-1) is 1/x+1