What is the inverse of f(x)=ln((e^x)/(e^{x-1)}) ?

The inverse of f(x)=ln((e^x)/(e^{x-1)}) is None

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=ln((e^x)/(e^{x-1)})

inverse

f (x) = ln (\frac{e ^{x}}{e ^{x - 1}})

None

Solution steps

y = ln (\frac{e ^{x}}{e ^{x - 1}})

Replace

x

with

y

x = ln (\frac{e ^{y}}{e ^{y - 1}})

Solve for

y, x = ln (\frac{e ^{y}}{e ^{y - 1}})

Therefore, there are no inverse functions for

ln (\frac{e ^{x}}{e ^{x - 1}})

None

What is the inverse of f(x)=ln((e^x)/(e^{x-1)}) ?
The inverse of f(x)=ln((e^x)/(e^{x-1)}) is None