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Popular Functions >

inverse of (x-2)^2+1,x>= 2

Solution

inverse

(x - 2)^{2} + 1, x \geq 2

Solution

x - 1 + 2, - x - 1 + 2

Solution steps

y = (x - 2)^{2} + 1

Replace

x

with

y

x = (y - 2)^{2} + 1

Solve for

y, x = (y - 2)^{2} + 1

x - 1 + 2, - x - 1 + 2

Graph

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Frequently Asked Questions (FAQ)

What is the inverse of (x-2)^2+1,x>= 2 ?
The inverse of (x-2)^2+1,x>= 2 is sqrt(x-1)+2,-sqrt(x-1)+2