What is the domain of f(x)= 9/(\frac{1){x-3}+1} ?

The domain of f(x)= 9/(\frac{1){x-3}+1} is x 3

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domain of f(x)= 9/(\frac{1){x-3}+1}

domain

f (x) = \frac{9}{\frac{1}{x - 3} + 1}

x < 2 or 2 < x < 3 or x > 3

Interval Notation

(- \infty, 2) \cup (2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = 3

The function domain

x < 2 or 2 < x < 3 or x > 3

What is the domain of f(x)= 9/(\frac{1){x-3}+1} ?
The domain of f(x)= 9/(\frac{1){x-3}+1} is x<2\lor 2<x<3\lor x>3