What is the inverse of f(x)=x^2+3x+6 ?

The inverse of f(x)=x^2+3x+6 is (-3+sqrt(4x-15))/2 ,(-3-sqrt(4x-15))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=x^2+3x+6

inverse

f (x) = x^{2} + 3 x + 6

\frac{- 3 + 4 x - 15}{2}, \frac{- 3 - 4 x - 15}{2}

Solution steps

y = x^{2} + 3 x + 6

Replace

x

with

y

x = y^{2} + 3 y + 6

Solve for

y, x = y^{2} + 3 y + 6

\frac{- 3 + 4 x - 15}{2}, \frac{- 3 - 4 x - 15}{2}

What is the inverse of f(x)=x^2+3x+6 ?
The inverse of f(x)=x^2+3x+6 is (-3+sqrt(4x-15))/2 ,(-3-sqrt(4x-15))/2