What is the inverse of f(x)=log_{10}(4^{x+2}) ?

The inverse of f(x)=log_{10}(4^{x+2}) is (xln(10))/(2ln(2))-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)=log_{10}(4^{x+2})

inverse

f (x) = lo g_{10} (4^{x + 2})

\frac{x ln ( 10 )}{2 ln ( 2 )} - 2

Solution steps

y = lo g_{10} (4^{x + 2})

Replace

x

with

y

x = lo g_{10} (4^{y + 2})

Solve for

y, x = lo g_{10} (4^{y + 2})

\frac{x ln ( 10 )}{2 ln ( 2 )} - 2

What is the inverse of f(x)=log_{10}(4^{x+2}) ?
The inverse of f(x)=log_{10}(4^{x+2}) is (xln(10))/(2ln(2))-2