What is the inverse of y+5=log_{0.7}(3x-2) ?

The inverse of y+5=log_{0.7}(3x-2) is (0.7^{x+5}+2)/3

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inverse of y+5=log_{0.7}(3x-2)

inverse

y + 5 = lo g_{0.7} (3 x - 2)

\frac{0. 7 ^{x + 5} + 2}{3}

Solution steps

y = lo g_{0.7} (3 x - 2) - 5

Replace

x

with

y

x = lo g_{0.7} (3 y - 2) - 5

Solve for

y, x = lo g_{0.7} (3 y - 2) - 5

\frac{0. 7 ^{x + 5} + 2}{3}

What is the inverse of y+5=log_{0.7}(3x-2) ?
The inverse of y+5=log_{0.7}(3x-2) is (0.7^{x+5}+2)/3