What is the inverse of ((s+1))/(s^2+2s+10) ?

The inverse of ((s+1))/(s^2+2s+10) is (-2s+1+sqrt(-36s^2+1))/(2s),(-2s+1-sqrt(-36s^2+1))/(2s)

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inverse of ((s+1))/(s^2+2s+10)

inverse

\frac{( s + 1 )}{s ^{2} + 2 s + 10}

\frac{- 2 s + 1 + - 36 s ^{2} + 1}{2 s}, \frac{- 2 s + 1 - - 36 s ^{2} + 1}{2 s}

Solution steps

y = \frac{s + 1}{s ^{2} + 2 s + 10}

Replace

s

with

y

s = \frac{y + 1}{y ^{2} + 2 y + 10}

Solve for

y, s = \frac{y + 1}{y ^{2} + 2 y + 10}

\frac{- 2 s + 1 + - 36 s ^{2} + 1}{2 s}, \frac{- 2 s + 1 - - 36 s ^{2} + 1}{2 s}

What is the inverse of ((s+1))/(s^2+2s+10) ?
The inverse of ((s+1))/(s^2+2s+10) is (-2s+1+sqrt(-36s^2+1))/(2s),(-2s+1-sqrt(-36s^2+1))/(2s)