What is the inverse of (1e^-(2s))/((s^2-s)) ?

The inverse of (1e^-(2s))/((s^2-s)) is (2e^)/s+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of (1e^-(2s))/((s^2-s))

inverse

\frac{1 e ^{-} ( 2 s )}{( s ^{2} - s )}

\frac{2 e}{s} + 1

Solution steps

y = \frac{1 \cdot e ^{-} \cdot 2 s}{s ^{2} - s}

Replace

s

with

y

s = \frac{1 \cdot e ^{-} \cdot 2 y}{y ^{2} - y}

Solve for

y, s = \frac{1 e ^{-} 2 y}{y ^{2} - y}

\frac{2 e}{s} + 1

What is the inverse of (1e^-(2s))/((s^2-s)) ?
The inverse of (1e^-(2s))/((s^2-s)) is (2e^)/s+1