What is the inverse of 8/(x^2-x-6) ?

The inverse of 8/(x^2-x-6) is (x+sqrt(25x^2+32x))/(2x),(x-sqrt(25x^2+32x))/(2x)

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inverse of 8/(x^2-x-6)

inverse

\frac{8}{x ^{2} - x - 6}

\frac{x + 25 x ^{2} + 32 x}{2 x}, \frac{x - 25 x ^{2} + 32 x}{2 x}

Solution steps

y = \frac{8}{x ^{2} - x - 6}

Replace

x

with

y

x = \frac{8}{y ^{2} - y - 6}

Solve for

y, x = \frac{8}{y ^{2} - y - 6}

\frac{x + 25 x ^{2} + 32 x}{2 x}, \frac{x - 25 x ^{2} + 32 x}{2 x}

What is the inverse of 8/(x^2-x-6) ?
The inverse of 8/(x^2-x-6) is (x+sqrt(25x^2+32x))/(2x),(x-sqrt(25x^2+32x))/(2x)