What is the inverse of 8(2x+10)^2+3 ?

The inverse of 8(2x+10)^2+3 is (sqrt(2)sqrt(x-3)-40)/8 ,(-sqrt(2)sqrt(x-3)-40)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of 8(2x+10)^2+3

inverse

8 (2 x + 10)^{2} + 3

\frac{2 x - 3 - 40}{8}, \frac{- 2 x - 3 - 40}{8}

Solution steps

y = 8 (2 x + 10)^{2} + 3

Replace

x

with

y

x = 8 (2 y + 10)^{2} + 3

Solve for

y, x = 8 (2 y + 10)^{2} + 3

\frac{2 x - 3 - 40}{8}, \frac{- 2 x - 3 - 40}{8}

What is the inverse of 8(2x+10)^2+3 ?
The inverse of 8(2x+10)^2+3 is (sqrt(2)sqrt(x-3)-40)/8 ,(-sqrt(2)sqrt(x-3)-40)/8