What is the inverse of y=(x^2)/2+2x ?

The inverse of y=(x^2)/2+2x is (-4+sqrt(16+8x))/2 ,(-4-sqrt(16+8x))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of y=(x^2)/2+2x

inverse

y = \frac{x ^{2}}{2} + 2 x

\frac{- 4 + 16 + 8 x}{2}, \frac{- 4 - 16 + 8 x}{2}

Solution steps

y = \frac{x ^{2}}{2} + 2 x

Replace

x

with

y

x = \frac{y ^{2}}{2} + 2 y

Solve for

y, x = \frac{y ^{2}}{2} + 2 y

\frac{- 4 + 16 + 8 x}{2}, \frac{- 4 - 16 + 8 x}{2}

What is the inverse of y=(x^2)/2+2x ?
The inverse of y=(x^2)/2+2x is (-4+sqrt(16+8x))/2 ,(-4-sqrt(16+8x))/2